Question

solve
$9g { }^{2}= 6(g + 20)$
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Answer 1

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${9g}^{2} = 6(g + 20) \\ {9g}^{2} = 6g + 120 \\ \: divide \: both \: side \: by3 \\ 3 {g}^{2} - 2g - 40 = 0 \\ \\ {3g}^{2} - 12g + 10g - 40 \\ \\ 3g(g - 4) + 10(g - 4) \\ \\ (3g + 10)(g - 4)$

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Answer 2

Answer:

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