Math, asked by NilotpalSwargiary, 9 months ago

Solve:
 {a}^{2}  {x}^{2}  - 3abx + 2 {b}^{2}  = 0

Answers

Answered by rajvamsid
0

Answer:

x=b/a or -2b/a

Step-by-step explanation:

a^2x^2-3abx+2b^2

a^2x^2-2abx-abx+2b^2

ax(ax-2b)-b(ax+2b)

(ax-b)(ax+2b)

x=b/a or -2b/a

Answered by InfiniteSoul
3

\sf{\underline{\boxed{\green{\large{\bold{ Solution}}}}}}

\sf \implies {a}^{2} {x}^{2} - 3abx + 2 {b}^{2} = 0

\sf\implies a^2x^2 - 2abx - abx + 2b^2 = 0

\sf\implies ax ( ax - 2b ) - b ( ax - 2b ) = 0

\sf\implies ( ax - b ) ( ax - 2b ) = 0

\sf ( ax - b ) = 0

\sf\longrightarrow ax = b

\sf\longrightarrow x = \dfrac{b}{a}

\sf{\red{\boxed{\bold{\dag x = \dfrac{b}{a}}}}}

\sf ( ax - 2b ) = 0

\sf\longrightarrow ax = 2b

\sf\longrightarrow x = \dfrac{2b}{a}

\sf{\red{\boxed{\bold{\dag x = \dfrac{2b}{a}}}}}

___________________❤

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