Question

Solve:

$\displaystyle \lim_{x \to 2} f \left{ \frac{x^2-4}{x-2} \right}$​

Answer 1

Answer:

The answer is 4

Step-by-step explanation

$\lim_{x \to \two} _2 \frac{x^{2}-4 }{x-2} = \lim_{x \to _2 \frac{(x-2)(x+2)}{(x-2)}$  

the x-2 in the numertaor and denominator get cancelled and then, you will get

$\lim_{x \to \two} _2$  x + 2 = 2 + 2 = 4