Question

Solve:
$\displaystyle \lim_{x \to 2} \frac{x^2-4}{x-2}$

Answer 1

Step-by-step explanation:

$\sf \lim_{x \to 2} \frac {{x}^{2} - 4 }{x - 2}$

=$\sf \lim_{x \to 2} \frac {(x - 2) (x + 2 )}{x - 2}$

=$\sf \lim_{ x \to 2 } x + 2$

=$\sf 2 + 2$

= $\sf 4$

THANKS!!!