Question

Solve: $dx/dt+4x+3y=t, dy/dt+2x+5y=e^t$

Answer 1

[math]\frac{dx}{dt} + 4x + 3y = t, \frac{dy}{dt} + 2x + 5y = e^t[/math] Laplace ... (2xy+y-Tany) dx+ (x^2-x [Tany] ^2 + [secy] ^2+2) dy=0 , (te^ [TX] +2x) dx/dt+xe [xt] +0?