Math, asked by adhyayan56, 8 months ago

solve:
 \frac{(17-3y)}{5} -{ \frac{(4y + 2)}{3} }=5-6y+\frac{(7y+14)}{3}

Answers

Answered by Anonymous
8

Answer:

Given:-

 \dfrac{17 - 3y}{5} - \dfrac{4y + 2}{3} = 5 - 6y + \dfrac{7y + 14}{3}

Solution:-

 \dfrac{17 - 3y}{5} - \dfrac{4y + 2}{3} = 5 - 6y + \dfrac{7y + 14}{3}

 \dfrac{17 - 3y}{5} -5 + 6y =  \dfrac{7y + 14}{3}</p><p>+ \dfrac{4y + 2}{3}

 \dfrac{17 - 3y-25 + 30y}{5}=\dfrac{7y + 14 +4y + 2}{3}

 \dfrac{ 27y - 8}{5} =  \dfrac{11y + 16}{3}

⇒61y - 24 = 55y + 80

⇒61y - 55y = 80 + 24

⇒6y = 104

⇒y =  \dfrac{104}{6}

⇒y = 17.33

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