Question

solve:
$\frac{(17-3y)}{5} -{ \frac{(4y + 2)}{3} }=5-6y+\frac{(7y+14)}{3}$
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Answer 1

Answer:

Given:-

$\dfrac{17 - 3y}{5} - \dfrac{4y + 2}{3} = 5 - 6y + \dfrac{7y + 14}{3}$

Solution:-

⇒$\dfrac{17 - 3y}{5} - \dfrac{4y + 2}{3} = 5 - 6y + \dfrac{7y + 14}{3}$

⇒$\dfrac{17 - 3y}{5} -5 + 6y = \dfrac{7y + 14}{3}</p><p>+ \dfrac{4y + 2}{3}$

⇒$\dfrac{17 - 3y-25 + 30y}{5}=\dfrac{7y + 14 +4y + 2}{3}$

⇒$\dfrac{ 27y - 8}{5} = \dfrac{11y + 16}{3}$

⇒61y - 24 = 55y + 80

⇒61y - 55y = 80 + 24

⇒6y = 104

⇒y = $\dfrac{104}{6}$

⇒y = 17.33