Question

Solve :-

$\frac{2}{3} (5x + 4) - [ \: 6x - \frac{1 + x}{3} ] = \frac{x}{3} + \frac{1}{3}$
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Answer 1

Question :-

$\frac{2}{3} (5x + 4) - [6x - \frac{1 + x}{3} ] = \frac{x}{3} + \frac{1}{3}$

Solution :-

$\frac{2}{3} (5x + 4) - [ \: 6x - \frac{1 + x}{3} ] = \frac{x}{3} + \frac{1}{3} \\ \\ ⟹ \: \: \frac{2}{3} \: (5x + 4) - [6x - \frac{1 + x}{3} ] = \frac{x}{3} \: + \frac{1}{3} \\ \\ ⟹ \frac{2}{3} (5x + 4) - [ \frac{18x - 1 - x}{3} ] = \frac{x + 1}{3} \\ \\ ⟹ \: \: \frac{10x + 8}{3} - \: \frac{17 - 1}{3} = \frac{x + 1}{3}$

Multiplying both sides by 3 we get :

$⟹ \: \: 10x + 8 - 17x + 1 = x + 1 \\ \\ ⟹ \: \: - 7x + 9 = x + 1 \\ \\ ⟹ - 7x - x = 1 - 9 \\ \\ ⟹ \: \: - 8x = - 8 \\ \\ ⟹ \: \: x = 1$