Question

Solve $\frac{2x+1}{3x+5} =\frac{11}{20}$.
Please answer quickly. Step-by-step explanation required. No spam allowed.

Answer 1

$\huge\bf\pink{\mid{\overline{\underline{Your\: Answer}}}\mid}$

$\underline{\underline{\huge\mathfrak{X=5}}}$

step-by-step explanation:

Given,

$\frac{2x+1}{3x+5} =\frac{11}{20}$

On cross multiplication,

we get,

=> 20(2x+1) = 11(3x+5)

=> 40x + 20 = 33x + 55

=> 40x - 33x = 55 - 20

On simplification,

we get,

=> 7x = 35

Now dividing both sides with 7,

we get,

=> x = 35/7

=> x = 5

Answer 2

$\huge {\bf{\red{\fbox{\underline {Heya !!}}}}}$

$\huge{SOLUTION}$

$\frac{2x + 1}{3x + 5 } = \frac {11}{20}$

=> 20(2x + 1 ) = 11 ( 3x + 5 )

=> 40x + 20 = 33x + 55

=> 40x - 33x = 55- 20

=> 7x = 35

=> x = 5

$\huge {ANSWER}$

x = 5