Question

solve:
$\frac{ {sin}^{2} 63 + {sin}^{2}27 }{ {cos}^{2}17 + {cos}^{2}73 }$
​

Answer 1

Answer:

1

Step-by-step explanation:

$\frac{sin {}^{2} 63 + sin ^{2} 27}{sin ^{2} 17 + {cos}^{2}73 } \\ \\ \frac{sin ^{2} (90 - 27) + {sin}^{2}27 }{ {cos}^{2}(90 - 73) + {cos}^{2} 73 } \\ \\ \frac{ {cos}^{2} 27 + {sin}^{2}27 }{sin ^{2}73 + {cos}^{2} 73 } \\ \\ \frac{1}{1} \\ \\ 1$

.

Using Identity

sin²@ + cos²@ = 1

sin (90 - @) = cos @

cos(90 - @) = sin @

Answer 2

(sin²63+sin²27)/cos²17+cos²73

=(sin²63+cos²63)/cos²17+sin²17

=1/1

=1

Using sin(90-θ)=cosθ and cos(90-θ)=sinθ

sin²θ+cos²θ= 1