Question

Solve
$\frac{ {x}^{4} - 6 {x}^{3} + 11 {x}^{2} - 6x }{x} \geqslant 0$
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Answer 1

${x}^{3} - 6 {x}^{2} + 11x - 6 \geqslant 0$

${x}^{3} - 5 {x}^{2} - {x}^{2} + 5x + 6x - 6 \geqslant 0$

${x}^{2} (x - 1) - 5x(x - 1) + 6(x - 1) \geqslant 0$

$(x - 1) ({x}^{2} - 5x + 6) > 0$

$(x - 1)(x - 3)(x - 2) \geqslant 0$

$x = 1 \: or \: x = 2 \: or \: x = 3$

From no. line we get that

X belongs to [1,2] union [3, infinity)

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Answer 2

Step-by-step explanation:

Heya Mate

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It refer to the attachment

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