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If we take direct substitution, -
Let us resolve this problem. The problem arises from the form of the fraction.
We rationalize the numerator by use of the identity.
So, -
*You can view the graph at .
We see that values near gets closer and closer to 1, but is discontinuous at .
We found the limiting value because we defined a new continuous function that is defined at , which we can find by substitution.
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