Question

solve
$log_{x}(2x - 3 \div 4) > 2$
and find the values of x.​

Answer 1

Answer:

the correct answer is.

Step-by-step explanation:

=4log2x-2x-3=0

⇒22(log2x)-2x-3=0

⇒2log2x2-2x-3=0

⇒x2-2x-3=0 (As alogab=b)

⇒x2-3x+x-3=0

⇒x(x-3)+1(x-3)=0

⇒(x-3)(x+1)=0

x=3andx=-1

But, x can not be negative,

[So, x=3]