Question

solve:
$\sqrt{2 - \sqrt{3} } \div \sqrt{2 + \sqrt{3} }$
​

Answer 1

Answer:

$2 - \sqrt{3}$

Step-by-step explanation:

$\frac{ \sqrt{2 - \sqrt{3} } }{ \sqrt{2 + \sqrt{3} } } \\ = \sqrt{ \frac{2 - \sqrt{3} }{2 + \sqrt{ 3} } } \\ = \sqrt{ \frac{ {(2 - \sqrt{3} )}^{2} }{(2 - \sqrt{3} ) (2 + \sqrt{3} )} } \\ = \sqrt{ \frac{ {(2 - \sqrt{3}) }^{2} }{ 4 - 3 } } \\ = \sqrt{ \frac{ {(2 - \sqrt{3}) }^{2} }{1} } \\ = \sqrt{ {(2 - \sqrt{3}) }^{2} } \\ = 2 - \sqrt{3}$

Pls mark branliest.