Question

Solve:$\sqrt{2x+9} -\sqrt{x-4} =3$

Answer 1

Answer:

20,8

Step-by-step explanation:

$\sqrt{2x+9} =\sqrt{x-4} +3$

$(\sqrt{2x+9} )^2=(\sqrt{x-4} +3)^2\\\\2x+9=x-4+9+6\sqrt{x-4} \\\\-6\sqrt{x-4} =-2x-9+x-4+9\\\\6\sqrt{x-4} =x+4\\\\(6\sqrt{x-4}) ^2=(x+4)^2\\\\36x-144=x^2+8x+16\\\\x^2-28x+160=0\\\\x^2-20x-8x+160=0\\x(x-20)-8(x-20)=0\\\\x=20,8$