Question

solve :
$\sqrt{3 {x} ^{2} } - 2 \sqrt{2x - 2 \sqrt{3 = 0} } .$
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Answer 1

Answer:

√3x2 -2√2x-2√3=0, the given equation is quadratic equation.

It's form is ax2+bx+c=0.

a= √3, b= -2√2 , c= -2√3 .

Hence x= -b±√(b^2-4ac)/2a.

x= 2√2± √(8 +24)/2√3.

x= 2√2± √(32)/2√3 = x= (2√2±4√2)/2√3,

x= (2√2+4√2)/ 2√3 and ( 2√2-4√2) / 2√3 .

We get √6 and -√6/3. Hence the values of x are √6 and -√6/3

Hope this helps you......