Math, asked by Amberkhemani, 24 days ago

solve
 \sqrt{3x + 18 } = x

Answers

Answered by jayshreejada109
0

Step-by-step explanation:

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Answered by anupkushwahampt
0

Step-by-step explanation:

√(3x + 18) = x

Square:

3x + 18 = x2

Subtract x2:

-x2 + 3x + 18 = 0

Multiply both sides by -1:

x2 - 3x - 18 = 0

So to factor we need m + n = -3 and mn = -18

-6 + 3 = -3

-6 * 3 = -18

(x - 6) (x + 3) = 0

x = 6 or -3

Note that since we used a squaring function, now more than ever we need to check our possibilities:

√(3 * -3 + 18) = -3

We can't get a negative when we root unless we use imaginary numbers, so that's out.

√(3 * 6 + 18) = 6

√(18 + 18) = 6

√36 = 6

6 = 6

So x = 6

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