Question

solve
$x {}^2 + 3x + 5 = 0$
​

Answer 1

hey ❗❗

given here

x²+3x+5=0

by using Dharacharya formula

x= [-b±√{b²-4ac}]/2a

here

a=1,b=3,c=5

so,

x= [-(3)±√{3²-4×1×5}]/2

x= [-3±√(9-20)]/2

x= [-3±√-11]/2

x= [-3± i√11]/2

[ i= √-1 ]

now take + and - ve sign

we get

first +ve sign

x= (-3+i√11)/2

second take -ve sign

x= (-3-i√11)/2

I hopes its help's u

[text]<b>[/text][/text]<marquee>Follow me....✌✌</marquee>[/text]

@Abhi.❤❤