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hey ❗❗
given here
x²+3x+5=0
by using Dharacharya formula
x= [-b±√{b²-4ac}]/2a
here
a=1,b=3,c=5
so,
x= [-(3)±√{3²-4×1×5}]/2
x= [-3±√(9-20)]/2
x= [-3±√-11]/2
x= [-3± i√11]/2
[ i= √-1 ]
now take + and - ve sign
we get
first +ve sign
x= (-3+i√11)/2
second take -ve sign
x= (-3-i√11)/2
I hopes its help's u
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@Abhi.❤❤
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