Question

solve
$(x + 2)( x + 3) - (x - 1)(x - 2) = 7$
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Answer 1

$\large{\bf{(x + 2)(x + 3) - (x - 1)(x - 2) = 7} }\\ \\ \rightarrow \large{ \sf{( {x}^{2} + 3x + 2x + 6) - ( {x}^{2} - 2x - x + 2) = 7 }} \\ \\ \large{\rightarrow \sf{( {x}^{2} + 5x + 6) - ( {x}^{2} - 3x + 2) = 7 }} \\ \\ \rightarrow \large{\sf{ \cancel{ {x}^{2} } + 5x + 6 - \cancel{ {x}^{2} }+ 3x - 2 = 7 }} \\ \\ \rightarrow \large{ \sf{8x + 4 = 7}} \\ \\ \rightarrow \large{ \sf{8x = 7 - 4}} \\ \\ \rightarrow \fbox{ \large{\sf{x = \dfrac{3}{8} }}}$

Answer 2

Answer:

(x^2+2x+3x+6)-(x^2-x-2x+2)=7

x^2+5x+6-x^2+x+2x-2=7

6x+2x+6-2=7

8x+4=7

8x+4-7=0

8x-3=0