Question

Solve 
$x(x + 4) = x ^{2} + 8x - 4$
​

Answer 1

Step-by-step explanation:

We have,

$x(x + 4) = {x}^{2} + 8x - 4$

$x(x) + x(4) = {x}^{2} + 8x - 4$

${x}^{2} + 4x = {x}^{2} + 8x - 4$

$4x = 8x - 4$

$4x - 8x = - 4$

$- 4x = - 4$

$x = \frac{ - 4}{ - 4}$

$x = 1$

Answer 2

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