Question

Solve: $(x+y)^{2} \time (x-y)^{2}$

Answer 1

Note: Check this attachment..!!

Answer 2

⏬(x+y)2 × (x-y)2⏬

(x+y)^2 - (x-y)^2 = 0

(x+y)^2 = x^2 +2xy +y^2

(x-y)^2 = x^2 -2xy + y^2

(x+y)^2 - (x-y)^2 = x^2 +2xy +y^2 - (x^2 -2xy + y^2) = x^2 +2xy +y^2 - x^2 +2xy - y^2 = x^2 -x^2 +2xy +2xy +y^2 -y^2 = 4xy

So (x+y)^2 - (x-y)^2 = 0 is not true.

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