Question

solve that ,6^2x+4 =3^3x×2^x+8​

Answer 1

so the answer is -2.

Answer 2

The value of x is 4.

Step-by-step explanation:

The given equation is

$6^{2x+4}=3^{3x}\times 2^{x+8}$

It can be rewritten as

$(3\times 2)^{2x+4}=3^{3x}\times 2^{x+8}$

Using the properties of exponent we get

$(3)^{2x+4}\times (2)^{2x+4}=3^{3x}\times 2^{x+8}$            $[\because (ab)^x=a^xb^x]$

On comparing the exponent of 3, we get

$2x+4=3x$

$4=3x-2x$

$4=x$

On comparing the exponent of 2, we get

$2x+4=x+8$

$2x-x=8-4$

$x=4$

Therefore, the value of x is 4.

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