Solve that A(1, 0) B (0, 1) C(1, 2) D(2, 1) are vertical s of parallelogram ABCD is ABCD rectangle
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Here AB =
(3+1)
2
+(1−0)
2
=
17
BC=
(2−3)
2
+(2−1)
2
=
2
CD=
(−2−2)
2
+(1−2)
2
=
17
AD=
(−2+1)
2
+(1−0)
2
=
2
Here,AB=CD and BC=AD
Therefore its a parallelogram
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