Question

Solve that if 2(a^2+b^2)=(a+b)^2 then a=b

Answer 1

Step-by-step explanation:

Given that,   $2(a^{2} +b^{2})= (a+b)^{2}$

              =>  $2a^{2}+2b^{2}= a^{2} +b^{2}+2ab$

              =>  $a^{2}+b^{2}-2ab=0$

              => $(a-b)^{2}=0$

              =>  $a-b=0$

              =>  $a = b$

Hence, proved.

Answer 2

Step-by-step explanation:

$2(a^{2}+b^{2}) = (a+b)^{2}$

Condition:- a = b

So,

$2(a^{2}+b^{2}) = (a+b)^{2}$

2 x $2a^{2}$ = $2b^{2}$

$a^{2} = \frac{b^{2} }{2}$

a = $\frac{b}{\sqrt{2} }$

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