Math, asked by jannet124, 1 year ago

solve that..
its urgent.....

guyzzzz do it fast.........​

Attachments:

jannet124: ????
sivaprasath: or 10,. I'm not so sure,.
jannet124: okkk
jannet124: solution beb
sivaprasath: I know 3^(6^1) = 3^6 = 729
jannet124: where it is???
sivaprasath: 3 + 6 + 1 = 10
jannet124: okk
jannet124: i'm sorryyyyyyyyyyyyyyyyyyyyyy but u also posses it
sivaprasath: That's why I'm titled maths Aryabhatta ,.

Answers

Answered by adityakrraj
3

Answer:

it is 3+6+2

Step-by-step explanation:

all possible formats are

3 ^ 6 ^ 1

9 ^ 3 ^ 1

27 ^ 2 ^1

so clearly the first one is the most appropriate

Answered by sivaprasath
0

Answer:

a + b + c = 10

Step-by-step explanation:

Given :

a^{b^{c}} = 729

Then, the minimum possible value of :

a + b + c = ?

Solution :

We know that,

For minimum value of exponents,.

The base value should be minimum,.

⇒ The minimum possible whole number is 3 ⇒ a = 3

We know that,

729 = 3^6

6 = b^c

This is possible when b = 6 & c = 1

i.e., 729 = 3^{6^{1}}

⇒ a = 3 , b = 6 , c = 1,.

⇒ a + b + c = 3 + 6 + 1 = 10

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