Question

solve that..
its urgent.....

guyzzzz do it fast.........​

Answer 1

Answer:

it is 3+6+2

Step-by-step explanation:

all possible formats are

3 ^ 6 ^ 1

9 ^ 3 ^ 1

27 ^ 2 ^1

so clearly the first one is the most appropriate

Answer 2

Answer:

a + b + c = 10

Step-by-step explanation:

Given :

$a^{b^{c}} = 729$

Then, the minimum possible value of :

a + b + c = ?

Solution :

We know that,

For minimum value of exponents,.

The base value should be minimum,.

⇒ The minimum possible whole number is 3 ⇒ a = 3

We know that,

$729 = 3^6$

⇒ $6 = b^c$

This is possible when b = 6 & c = 1

i.e., $729 = 3^{6^{1}}$

⇒ a = 3 , b = 6 , c = 1,.

⇒ a + b + c = 3 + 6 + 1 = 10