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➡q₁ A------------M------------B q₂
Let two charge q₁ = 400 μC and q₂ = 200 μC are placed A and B respectively and M is the midpoint of AB .
➡q₁ and q₂ both are positive charge . Means net electric field, E = E₁ - E₂ [ due to both the charge creates electric fleid in opposite direction as shown in figure,
Now, electric field due to q₁ = E₁ = kq₁/AM² [ AM = MB = 0.3m , from above daigram]
E₁ = 9 × 10⁹ × 400 × 10⁻⁶/(0.3)² = 4 × 10⁵ N/C
➡Similarly electric field due to q₂ = E₂ = Kq₂²/MB²
E₂ = 9 × 10⁹ × 200 × 10⁻⁶/(0.3)² = 2 × 10⁵ N/C
✔✔Hence, net electric field at middle point = E₁ - E₂ = 4 × 10⁵ - 2 × 10⁵ = 2 × 10⁵N/C
________________________________
hope it helps you!!☺☺
here's your answer!!☺☺
_________________________________
➡q₁ A------------M------------B q₂
Let two charge q₁ = 400 μC and q₂ = 200 μC are placed A and B respectively and M is the midpoint of AB .
➡q₁ and q₂ both are positive charge . Means net electric field, E = E₁ - E₂ [ due to both the charge creates electric fleid in opposite direction as shown in figure,
Now, electric field due to q₁ = E₁ = kq₁/AM² [ AM = MB = 0.3m , from above daigram]
E₁ = 9 × 10⁹ × 400 × 10⁻⁶/(0.3)² = 4 × 10⁵ N/C
➡Similarly electric field due to q₂ = E₂ = Kq₂²/MB²
E₂ = 9 × 10⁹ × 200 × 10⁻⁶/(0.3)² = 2 × 10⁵ N/C
✔✔Hence, net electric field at middle point = E₁ - E₂ = 4 × 10⁵ - 2 × 10⁵ = 2 × 10⁵N/C
________________________________
hope it helps you!!☺☺
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