Question

solve that question its so important

Answer 1

Hey mate!

Here's your answer!!

Given Sin 10 Sin 30 Sin 50 sin 70
⇒ (1/ 2) Sin 10 Sin 50 sin 70

⇒ 2 Cos 10 Sin 10 Sin 50 sin 70 / (2 x 2 Cos 10) { 2SinA Cos A = Sin2A }

⇒ Sin 20 Sin 50 sin 70 / ( 4 Cos 10)

⇒ 2 x Sin 20 Sin 50 sin (90 - 20) /(2 x 4 Cos 10)

⇒ 2 Sin 20 Cos 20 Sin 50 / 8 Cos 10

⇒ Sin 40 Sin 50 / 8 Cos 10 { 2SinA Cos A = Sin2A }

⇒ 2 x Sin 40 Sin ( 90 - 40) / 2 x 8 Cos 10.

⇒ 2 x Sin 40 Cos 40 / 2 x 8 Cos ( 90 - 80)

⇒ Sin 80 / 16 Sin 80 = 1 / 16.

$hope \: it \: helps \: you....$
✌ ✌ ✌

Answer 2

heya....

Here is your answer it may help you..☺☺