solve that root 2 cos theta + 1 = 0
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Hey mate
Your answer:
√2cos∅+1=0
√2cos∅=-1
cos∅=-1/√2
cos∅=-cos45
sorry the question appears to wrong as measures of angles cannot be negative
Your answer:
√2cos∅+1=0
√2cos∅=-1
cos∅=-1/√2
cos∅=-cos45
sorry the question appears to wrong as measures of angles cannot be negative
Answered by
1
Going to sleep....................
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