solve that, sin⁻¹(x) + cos⁻¹(2x) = π÷6 , x=?
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Answer:
sin⁻¹(x) + cos⁻¹(2x) = π÷6
(x) =sin{ π/6 - cos^-1(2x)} ,
x= sin(π/6) 2x- cos(π/6) . sin(cos^-(2x)
x=x- (√3/2).√(1-x^2)
√(1-x^2)=0
x^2 = 1,
x= +1, -1
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