Question

Solve that v² = u² +2as by
using graph
by
v-t​

Answer 1

Answer:

Explanation:

we know : displacement = area under the velocity time graph .

S= area of trapezium ACEF

S= 1/2 ( b¹ + b² ) h

s= 1/2 ( AF+CE )FE

S= 1/2 ( U+ V) T

We know -v= u+ at

v-u/a= t

now 2 in 1

S= 1/2( v+u) (v-u)

2as= ( v+u) (v-u)

2as=v²-u²

[v² - u2 = 2as]

Answer 2

Answer:

We will use both of the equations of motion to reach the third equation of motion. This will require a bit of algebra.

S=ut+  

2

1

​  

at  

2

andv=u+at, include the time variant t

There will be some situations when we do not have any information about time and so it would be a good idea to derive an equation that does not have a t term.

To do this, we rearrange our first equation to get  

t=  

a

v−u

​  

 

and use this to replace t wherever it appears in the second equation. So

S=ut+  

2

1

​  

at  

2

 becomes,

S=u(  

a

v−u

​  

)+  

2

1

​  

a(  

a

v−u

​  

)  

2

 

⇒2aS=2u(v−u)+(v−u)  

2

 

⇒2aS=2uv−2u  

2

−v  

2

−2uv−u  

2

 

⇒2aS=v  

2

−u  

2

 

⇒v  

2

=u  

2

+2aS

Explanation: