solve that..........value of X and Y....................
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1=>b^2x+a^2y=ab(a^2+b^2)
2xb^2=>b^2x+b^2y=2ab^3
1-2=>y(a^2-b^2)=ab(a^2+b^2-2b^2)=ab(a^2-b^2)
y=ab
by 2
x=ab
2xb^2=>b^2x+b^2y=2ab^3
1-2=>y(a^2-b^2)=ab(a^2+b^2-2b^2)=ab(a^2-b^2)
y=ab
by 2
x=ab
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