Question

solve that y = sin (log x) ​

Answer 1

$\huge\frak{AnSwEr:-}$

We have y = sin (log x)

Differentiate w. r. t. x

$\frac{dx}{dy} = \frac{d}{dx} [sin( logx)] \\ \\ [Treat \: log x \: as \: u \: in \: mind \: and \: use \\ \\ \: the \: formula \: </p><p></p><p>of \: derivative \: of \: sin \: u]$

$\frac{dy}{dx} = \cos( log \: x ) \times \frac{d}{dx} ( log \: x) \\ \\ \frac{dy}{dx} = \cos( log \:x). \frac{1}{x} \\ \\ \frac{dy}{dx} = \frac{ \cos( log \: x) }{x} \:$

Answer 2

Answer:

$y = \sin( logx ) \\ = > log_{ \sin( logx ) }y = 1 \\ = > log_{ \sin( logx ) }(y) = log_{ \sin( logx) }0 \\ = > y = 0$