Question

solve the 10 and 11 ouestion plz help me

Answer 1

Hey dear!!


Here is yr answer.........



10.

Given,

Measures of two complementary angle are --

(3x+4) and (x-2)

we know,

Sum of both angles = 90°


So,

(3x+4) + (x-2) = 90°

4x+2 = 90°

4x = 90-2

4x = 88

x = 22


Therefore, x = 22°



11.


Given,

The measures of supplementary angles are--

(2x+10) and (3x+5)


Sum of both angles = 180°

(2x+10) + (3x+5) = 180°

5x+15 = 180°

5x = 180° - 15°

x = 165/5

x = 33°


Therefore, x = 33°



Hope it hlpz buddy.....

Answer 2

Hi!

Here is your Answer!

Q10)
Given that
Complementary angle
(3x+4)° and (x-2)°

We know that
Sum of Complementary angle = 90°
Now

3x+4+x-2 = 90°
4x =90-2
X = 88/4
X = 22
Put the Value X in angle

3×22+4= 66+4
= 70°
22-2 = 20°
_________________________

Q11)
Given that supplementary angle
We know that

The sum of supplementary angle= 180°

Now
2x +10 +3x+5 = 180°
5x +15 = 180°
5x = 165
X = 165/5
X = 33

Put the Value of X in angle

2×33+ 10 = 66+10 = 76°
3×33+5 = 99+5 = 104°

Hope it's helpful ✌✌