Question

Solve the 25^2x+1=15​

Answer 1

Answer:

I'm assuming you mean the 25^2 not 2x so it's 14/625

Step-by-step explanation:

(252)(x)+1=15

Step 1: Simplify both sides of the equation.

625x+1=15

Step 2: Subtract 1 from both sides.

625x+1−1=15−1

625x=14

Step 3: Divide both sides by 625.

625x/625=14/625

x= 14/625

Answer 2

Correct question is "Solve the 25²x+1=15 "

Answer:

Required value is $\frac{14}{625}$

Step-by-step explanation:

Given, ${25}^{2} x + 1 = 15$

We know,

${25}^{2} = 25 \times 25 \\ = 625$

So,

${25}^{2} x + 1 = 15 \\ 625x + 1 = 15 \\ 625x = 15 - 1 \\ 625x = 14 \\ x = \frac{14}{625}$

So, required value of x is $\frac{14}{625}$

This is a problem of Algebra part of Mathematics.

Some important Algebra's formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Two more important Algebra's problem:

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

#SPJ2