solve the 26 number question.
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Suppose, Internal Resistance = r
When the resistors are in parallel combination, then total resistance,
1/R1 = 1/2 + 1/2
1/R1 = 1
R1 = 1 ohm...●
And, Current = I1 = 1.2 A
Thus, emf of the cell = I1( R1 + r ).........equation 1.
Samely,
For Series combination,
R2 = 2 + 2
R2= 4 ohm...●
And, Current = I2 = 0.4 Ampere.
So, emf of the cell = I2(R2 + r).......equation 2.
Because, emf of the cell is same for all conditions, so from equation 1 and 2....
I1(R1 + r) = I2(R2 + r)
1.2(1 + r) = 0.4(4 + r)
3(1 + r) = 4 + r
3 + 3r = 4 + r
2r = 4 - 3
r = 1/2
r = 0.5 ohm....●●
Thus, Internal Resistance of the Cell = r = 0.5 ohm. ●
ii}. Now, emf of the cell,
From, equation 1.....
emf = I1( R1 + r )
= 1.2 ( 1 + 0.5 )
= 1.2 × 1.5
emf = 1.8 V...●●
Thus, emf of the cell = 1.8 V. ●
●●●●●●●●●●●●●●●●●●●●●
Hope it was helpful.
When the resistors are in parallel combination, then total resistance,
1/R1 = 1/2 + 1/2
1/R1 = 1
R1 = 1 ohm...●
And, Current = I1 = 1.2 A
Thus, emf of the cell = I1( R1 + r ).........equation 1.
Samely,
For Series combination,
R2 = 2 + 2
R2= 4 ohm...●
And, Current = I2 = 0.4 Ampere.
So, emf of the cell = I2(R2 + r).......equation 2.
Because, emf of the cell is same for all conditions, so from equation 1 and 2....
I1(R1 + r) = I2(R2 + r)
1.2(1 + r) = 0.4(4 + r)
3(1 + r) = 4 + r
3 + 3r = 4 + r
2r = 4 - 3
r = 1/2
r = 0.5 ohm....●●
Thus, Internal Resistance of the Cell = r = 0.5 ohm. ●
ii}. Now, emf of the cell,
From, equation 1.....
emf = I1( R1 + r )
= 1.2 ( 1 + 0.5 )
= 1.2 × 1.5
emf = 1.8 V...●●
Thus, emf of the cell = 1.8 V. ●
●●●●●●●●●●●●●●●●●●●●●
Hope it was helpful.
soumyakapis35pdtdz0:
Thanks.
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