solve the 2nd main question in the pic Plz!
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(1) side length of rhombus = radius of the circle = 10 cm
and the smaller diagonal divides the rhombus into two equilateral triangles., with side length 10 cm
area of equilateral triangle = √3a²/4 = √3 ×(10)²/4 = 25√3 cm²
so the area of rhombus = 2×25√3 = 50√3 cm²
(2) area of rhombus = 32√3 cm²
area of one equilateral triangle =(32√3)/2 = 16√3 cm²
and √3a²/4 = 16√3
⇒a² = 64
⇒a = 8 cm
and the smaller diagonal divides the rhombus into two equilateral triangles., with side length 10 cm
area of equilateral triangle = √3a²/4 = √3 ×(10)²/4 = 25√3 cm²
so the area of rhombus = 2×25√3 = 50√3 cm²
(2) area of rhombus = 32√3 cm²
area of one equilateral triangle =(32√3)/2 = 16√3 cm²
and √3a²/4 = 16√3
⇒a² = 64
⇒a = 8 cm
Hrithik1111:
tysm!!!?
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