Question

solve the 3 rd part​

Answer 1

❥${\purple{\underline{\underline{\large{\mathtt{ANSWER:-}}}}}}$

76

❥${\purple{\underline{\underline{\large{\mathtt{EXPLANATION:-}}}}}}$

• Given:-

• a ≠ 0
• $a-\frac{1}{a}=4$

•To find:-

• Value of $a^3-\frac{1}{a^3}$

•Solution:-

$\sf{a^3-\frac{1}{a^3}}$

$\sf{\implies{(a-\frac{1}{a})^3+3a\frac{1}{a}\:(a-\frac{1}{a})}}$

$\sf{\implies{4^2+3\times\:4}}$

$\sf{\implies{64+3\times\:4}}$

$\sf{\implies{64+12}}$

$\sf{\implies{76\:(Answer)}}$