solve the 3x^2+9x-6 and find its zeroes
Answers
Answer:
Step-by-step explanation:
3x2+9x-6=0
Two solutions were found :
x =(-3-√17)/2=-3.562
x =(-3+√17)/2= 0.562
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(3x2 + 9x) - 6 = 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
3x2 + 9x - 6 = 3 • (x2 + 3x - 2)
Trying to factor by splitting the middle term
3.2 Factoring x2 + 3x - 2
The first term is, x2 its coefficient is 1 .
The middle term is, +3x its coefficient is 3 .
The last term, "the constant", is -2
Step-1 : Multiply the coefficient of the first term by the constant 1 • -2 = -2
Step-2 : Find two factors of -2 whose sum equals the coefficient of the middle term, which is 3 .
-2 + 1 = -1
-1 + 2 = 1
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 3 :
3 • (x2 + 3x - 2) = 0
Step 4 :
Equations which are never true :
4.1 Solve : 3 = 0