Question

solve the 3y+5(2-y) =-16 by linear equations in one variable​

Answer 1

Answer:

y = 3

Step-by-step explanation:

3y + 5(2-y) = (-16)

3y + 10 - 5y = (-16)

-2y + 10 = (-16)

-2y = (-16) - 10

-2y = (-6)

y = (-6)/(-2)     [ minus and minus get cancelled over here]

y = 3

Answer 2

$\huge \fcolorbox {pink}{yellow}{Answer}$

$3 y + 5 ( 2 - y ) = 16$

$3y+10-5y=16$

$-2y+10=16$

$-2y=16-10$

$-2y=6$

Divide both sides by -2.

$y=\frac{6}{-2}$

Divide 6 by -2 to get -3.

$y=-3$

$\huge \fcolorbox {pink}{lightgreen}{y = - 3}$