Solve the 3y-7/5=1-y/-3 linear equation
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Answer:
3y-7/5=1-y/-3
(3y-7)*-3=(1-y)*5
-9y+21 = 5-5y
-9y+5y = 5-21
-4y = -16
4y = 16
y = 16/4
y = 4
Step-by-step explanation:
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