Solve The 6th Problem Please
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Answer:
C is 105⁰
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In a quadrilateral ABCD, <A=100°, <B=89° and <D=75°. Then find<C.
<A + <B + <C + <D = 360° (All the angle in a quadrilateral add upto 360°)
Let the unknown angle be y
==> <A + <B + y + <D = 360°
==> 100° + 80° + y + 75° = 360°
==> 255° + y = 360°
==> y = 360° - 255°
==> y = 105°
Therefore, <C = 105°
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