History, asked by simi2021, 5 hours ago

solve the 6th sum fast. plz.​

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Answers

Answered by Abhinav78036
1

Let the 2 numbers be x and y

We know that

xy= 36 and also

2/3 x= 6/5 y.

2/3 36/y = 6/5 y

24/y= 6y/5

y²= 20

Therefore y= 2√5

and x= 18/√5

Answered by abhinavmike85
0

\huge{✯}\huge{\underline{\underline{\mathcal{\sf{Answer}}}}}

\huge{☞} First Number = 23\dfrac{1}{7}

\huge{☞} Second Number = 12\dfrac{6}{7}

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\huge{✯} \huge{\underline{\underline{\mathcal{\sf{Given}}}}}

\dfrac{2}{3} of first number is equal to \dfrac{6}{5} of other number.

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\huge{✯} \huge{\underline{\underline{\mathcal{\sf{Steps}}}}}

Let first number be x.

Other number = 36-x

According to the question,

\large{⇒}\dfrac{2}{3} of x = \dfrac{6}{5} of (36-x)

\large{⇒}Sending x terms to LHS and constant terms to RHS,

\large{⇒} \dfrac{2}{3} x  =  \dfrac{6}{5} (36 - x) \\  \\\large{⇒}\dfrac{2}{3}x =  \dfrac{216}{5}   -  \dfrac{6}{5} x \\  \\ \large{⇒} \dfrac{2}{3} x +  \dfrac{6}{5} x =  \dfrac{216}{5}  \\  \\\large{⇒} \dfrac{10x + 18x}{15}  =  \dfrac{216}{5}  \\  \\ \large{⇒}28x =  \dfrac{216 \times 15}{5}  \\  \\\large{⇒} x =  \dfrac{216\times 15}{5 \times 28}  \\  \\ \: \large{⇒} x =  \dfrac{162}{7}  \\  \\\large{⇒} x = 23 \dfrac{1}{7}

\large{⇒}Second Number = 36-\dfrac{162}{7}

\large{⇒}Second Number = \dfrac{252-162}{7}

\large{⇒}Second Number = \dfrac{90}{7}

\large{⇒}Second Number = 12\dfrac{6}{7}

\\\\\fbox{\fbox{\fbox{\fbox{\huge{\underline{\underline{\sf{\green{Hope\:it\:helps}}}}}}}}}

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