Solve the 8x+3y=9 3x+2y =4 by elimination metho
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Heya!!!
8x + 3y = 9 -------- (1)
3x + 2y = 4 -------- (2)
In elimination method, we have to make any one variable same,
So, let's cancel 'x' variable by multiplying 8 in (2) and 3 in (1)
So,
{8x + 3y = 9} 3
{3x + 2y = 4} 8
⇒ 24x + 9y = 27 ---------- (3)
24x + 16y = 32 --------- (4)
By subtracting (4) from (3), we get,
24x + 9y = 27
- 24x - 16y = - 32
- 7y = - 5
y = - 5 / -7
y = 5 / 7
and from (1)
8x + 3 (5 / 7) = 9
8x + 15 / 7 = 9
56x + 15 = 63
56x = 63 - 15
56x = 48
x = 48 / 56
x = 6 / 7
So,
x = 6 / 7 and y = 5 / 7
Ways to cross - check the answer (EXTRA)
from (1)
8 (6 / 7) + 3 (5 / 7)
48 / 7 + 15 / 7
48 + 15 / 7
63 / 7
= 9 , which is same as given in (1),
So the solution is verified.
Thanks
8x + 3y = 9 -------- (1)
3x + 2y = 4 -------- (2)
In elimination method, we have to make any one variable same,
So, let's cancel 'x' variable by multiplying 8 in (2) and 3 in (1)
So,
{8x + 3y = 9} 3
{3x + 2y = 4} 8
⇒ 24x + 9y = 27 ---------- (3)
24x + 16y = 32 --------- (4)
By subtracting (4) from (3), we get,
24x + 9y = 27
- 24x - 16y = - 32
- 7y = - 5
y = - 5 / -7
y = 5 / 7
and from (1)
8x + 3 (5 / 7) = 9
8x + 15 / 7 = 9
56x + 15 = 63
56x = 63 - 15
56x = 48
x = 48 / 56
x = 6 / 7
So,
x = 6 / 7 and y = 5 / 7
Ways to cross - check the answer (EXTRA)
from (1)
8 (6 / 7) + 3 (5 / 7)
48 / 7 + 15 / 7
48 + 15 / 7
63 / 7
= 9 , which is same as given in (1),
So the solution is verified.
Thanks
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