Question

solve the above equation plz​

Answer 1

Answer:

$x^{2} +2\sqrt{2}x-6$

Step-by-step explanation:

$\alpha *\beta =\frac{c}{a} \\\\=>\sqrt{2}*(-3\sqrt{2})=\frac{-6}{1}\\\\\alpha +\beta=\frac{-b}{a}$

Given that a = 1 .

$\sqrt{2}+(-3\sqrt{2} ) =-b\\\\=>-2\sqrt{2}=-b\\\\ =>b=2\sqrt{2}$

We need to find quadratic equation.

=> $ax^{2} +bx+c$

Here a = 1 , b = $2\sqrt{2}$ , c = -6

Sub. values in the quadratic equation . We get ,

$=>x^{2} +2\sqrt{2}x-6$

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