Question

Solve the above equation with elimination method

Answer 1

Let the digits be x and y


Hence, the two digit number would be 10x + y



Given that, the number is 3 more than 4 times of the sum of its digits

=> 10x + y = 3 + 4(x + y)

=> 10x + y = 3 + 4x + 4y

=> 10x - 4x + y - 4y = 3

=> 6x - 3y = 3

=> 3(2x - y) = 3

=> 2x - y = 3/3

=> 2x - y = 1.............(equation 1)


Also, given that when 18 is added to the original number then the sum becomes the reverse of the original number.

=> 10x + y + 18 = 10y + x

=> 10x - x + y - 10y = - 18

=> 9x - 9y = - 18

=> 9y - 9x = 18

=> 9(y - x) = 18

=> y - x = 18/9

=> y - x = 2.............(equation 2)


Add eqn 1 and eqn 2

=> 2x - y + y - x = 1 + 2

=> x = 3


Now put the value of x in any equation to get y

y - x = 2

=> y - 3 = 2

=> y = 2 + 3

=> y = 5


Hence the two digit number is 10x + y

=> 10(3) + 5

=> 30 + 5

= 35


Your answer :- 35.

Hope it helps dear friend ☺️

Answer 2

This attachment is required answer.