solve the above given question
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Answer:
i have given you for 50,use it for 200
Explanation:
Length of scale is 20 cm and it can read upto 50 kg . hence, for maximum extension correspond to maximum weight . i.e 50 × 9.8 N
Use formula,
F = |Kx|
Where x = 20 cm = 20 × 10^-2 m
50 × 9.8 = K × 20 × 10^-2
K = 2450 N/m
We have for loaded oscillation
T = 2π √{m/K}
m = T²K/4π²
= (0.6)² × 2450/4×(3.14)²
= 22.36 Kg
weight = mg
= 22.36 × 9.8
= 219.13 N
this is a vertified answer from brainly.
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