Question

solve the above limits......!!

Answer 1

Answer:

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Answer 2

Write down the formula for finding the derivative using first principles *

g′(x)=limh→0g(x+h)−g(x)h *

Determine g(x+h) *

g(x)g(x+h)=2x−3=2(x+h)−3=2x+2h−3 *

Substitute into the formula and simplify

g′(x)=limh→02x+2h−3−(2x−3)h=limh→02hh=limh→02=2

Write the final answer *

The derivative g′(x)=2.