Question

solve the above please​

Answer 1

$\Large\mathtt\green{ }\huge\underline\mathtt\red{Answer : }$

3−23+2=a+b6

(3−2)(3+2)(3+2)2=a+b6

3−23+2+26=a+b6

5+26=a+b6

a=5 & b=2

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Answer 2

Answer:

3−23+2=a+b6

(3−2)(3+2)(3+2)2=a+b6

3−23+2+26=a+b6

5+26=a+b6

a=5 & b=2