Question

solve the above problem

Answer 1

In triangle ABC,

BC2 = AC2 + AB2 .............(equ.1)

In triangle ADC,

AC2 = AD2 + DC2 ...............(equ.2)

In triangle BAD,

AB2 = AD2 + BD2 .................(equ.3)

(equ.3 - equ.2)

AB2 - AC2 = BD2 - DC2

= (2BC)2 - (1BC)2

= 4BC2 - BC2

= 3BC2

= 3(AC2+AB2)

AB2 - AC2 = 3(AB2 + AC2)

AB2 + AC2 = 3(AB2 - AC2)

BC2 = 3(AB2 - AC2)