Solve the above question ⤴⤴⤴
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( xy ) ^2 = (2 xy -2 )
sq. root both sides
- xy = 2xy -2
- xy = 2
- x =2/ y
- y = 2 / x
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Answered by
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(xy) ^2 = (2 xy -2)
squaring roots on both sides
xy = 2xy -2
xy = 2
x =2/ y
y = 2 / x
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