Math, asked by yuvraj99975, 9 months ago

solve the above question​

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Answered by rachnahps17
1

Answer:

3^2*2^3

Mark as brainliest

Answered by malavikabala012003
1

=\sqrt[3]{\frac{3^{6}*4^{3}*2^{9} }{8^{6}*2^{6}  } }

=\sqrt[3]{\frac{3^{6}*2^{3}*2^{3} *2^{3}*2^{3}*2^{3}   }{2^{6}*2^{6}*2^{6}  *2^{6}  } }

=\sqrt[3]{\frac{3^{6}*2^{15}  }{2^{24} } }

=\sqrt[3]{\frac{3^{6} }{2^{9} } }

=\frac{3^{6*\frac{1}{3} } }{2^{9*\frac{1}{3} } }

=\frac{3^{2} }{2^{3} }

=\frac{9}{8}

Hope that answered your question.

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